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Where in the equation is a division?4(4-3-1)= 5(4-3-1)
(4-3-1)=0
4(0)= 5(0)
0=0
(4-3-1)=0
Cannot divide by zero, therefore (4-3-1)/(4-3-1) cannot be balanced out to become 1 as implied.
Factorisation ... left hand side has each number divided by 4 .... right hand side everything is divided by 5. these factors are placed outside the brackets.I can't see where the 5 comes in.
Division is part of the factorization process. (4-3-1) has been crossed out because of division that has occured in the process not shown.Anything multiplied by 0 = 0. Simple.
4(4-3-1) = 4x0 =0
Where in the equation is a division?